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Problem

We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11).

Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.

Example 1:

Input:
bits = [1, 0, 0]
Output: True
Explanation:
The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.

Example 2:

Input:
bits = [1, 1, 1, 0]
Output: False
Explanation:
The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.

Code

class Solution {
    public boolean isOneBitCharacter(int[] bits) {
        for (int i = 0; i < bits.length - 1; i++) {
            if (bits[i] == 0) continue;
            if (i + 1 == bits.length - 1) return false;
            i++;
        }

        return true;
    }
}