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## Problem

A web developer needs to know how to design a web page’s size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.
2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.

Return an array [L, W] where L and W are the length and width of the web page you designed in sequence.

Example 1:

Input: area = 4
Output: [2,2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1].
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.


Example 2:

Input: area = 37
Output: [37,1]


Example 3:

Input: area = 122122
Output: [427,286]


Constraints:

• 1 <= area <= 10^7

## Code

class Solution {
public int[] constructRectangle(int area) {
int base = (int)(Math.sqrt(area));

for(int i = base; i >= 1; i--){
if(area % i == 0){
return new int[]{area / i, i};
}
}

return new int[]{-1, -1};
}
}