JIAKAOBO

LeetCode

venmo
wechat

感谢赞助!

  • ㊗️
  • 大家
  • offer
  • 多多!

Problem

Given two strings s and t, check if s is a subsequence of t.

A subsequence of a string is a new string that is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (i.e., “ace” is a subsequence of “abcde” while “aec” is not).

Example 1:

Input: s = "abc", t = "ahbgdc"
Output: true

Example 2:

Input: s = "axc", t = "ahbgdc"
Output: false

Code

class Solution {
    public boolean isSubsequence(String s, String t) {
        if(s == null || s.length() == 0) return true;

        int curr = 0;
        for(char c : t.toCharArray()) {
            if(curr == s.length()) return true;
            if(c == s.charAt(curr)) {
                curr++;
            }
        }

        return curr == s.length();
    }
}

DP 解法

image tooltip here

class Solution {
    public boolean isSubsequence(String s, String t) {
        int sLen = s.length();
        int tLen = t.length();

        boolean[][] dp = new boolean[tLen + 1][sLen + 1];
        for(int i = 0; i <= tLen; i++){
            dp[i][0] = true;
        }

        for(int i = 1; i <= tLen; i++){
            for(int j = 1; j <= sLen; j++){
                if(dp[i - 1][j] == true){
                    dp[i][j] = true;
                } else if(t.charAt(i - 1) == s.charAt(j - 1) && dp[i - 1][j - 1] == true){
                    dp[i][j] = true;
                }
            }
        }

        return dp[tLen][sLen];
    }
}