223. Rectangle Area

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Problem

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

Example:

Input: A = -3, B = 0, C = 3, D = 4, E = 0, F = -1, G = 9, H = 2
Output: 45

Note:

Assume that the total area is never beyond the maximum possible value of int.

Code

class Solution {
    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int res = 0;
        int area1 = (C - A) * (D - B);
        int area2 = (G - E) * (H - F);

        int overlap = 0;

        // 大左，小右
        int leftMax = Math.max(A, E);
        int rightMin = Math.min(C, G);
        // 小上，大下
        int topMin = Math.min(D, H);
        int bottomMax = Math.max(B, F);

        if(leftMax < rightMin && topMin > bottomMax){
            overlap = Math.abs(rightMin - leftMax) * Math.abs(topMin - bottomMax);
        }

        return area1 + area2 - overlap;
    }
}