JIAKAOBO

LeetCode

venmo
wechat

感谢赞助!

  • ㊗️
  • 大家
  • offer
  • 多多！

Problem

Table: Users

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| user_id      | int     |
| user_name    | varchar |
| credit       | int     |
+--------------+---------+
user_id is the primary key for this table.
Each row of this table contains the current credit information for each user.

Table: Transactions

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| trans_id      | int     |
| paid_by       | int     |
| paid_to       | int     |
| amount        | int     |
| transacted_on | date    |
+---------------+---------+
trans_id is the primary key for this table.
Each row of this table contains information about the transaction in the bank.
User with id (paid_by) transfer money to user with id (paid_to).

Leetcode Bank (LCB) helps its coders in making virtual payments. Our bank records all transactions in the table Transaction, we want to find out the current balance of all users and check whether they have breached their credit limit (If their current credit is less than 0).

Write an SQL query to report.

  • user_id,
  • user_name,
  • credit, current balance after performing transactions, and
  • credit_limit_breached, check credit_limit (“Yes” or “No”)

Return the result table in any order.

The query result format is in the following example.

Example 1:

Input: 
Users table:
+------------+--------------+-------------+
| user_id    | user_name    | credit      |
+------------+--------------+-------------+
| 1          | Moustafa     | 100         |
| 2          | Jonathan     | 200         |
| 3          | Winston      | 10000       |
| 4          | Luis         | 800         | 
+------------+--------------+-------------+
Transactions table:
+------------+------------+------------+----------+---------------+
| trans_id   | paid_by    | paid_to    | amount   | transacted_on |
+------------+------------+------------+----------+---------------+
| 1          | 1          | 3          | 400      | 2020-08-01    |
| 2          | 3          | 2          | 500      | 2020-08-02    |
| 3          | 2          | 1          | 200      | 2020-08-03    |
+------------+------------+------------+----------+---------------+
Output: 
+------------+------------+------------+-----------------------+
| user_id    | user_name  | credit     | credit_limit_breached |
+------------+------------+------------+-----------------------+
| 1          | Moustafa   | -100       | Yes                   | 
| 2          | Jonathan   | 500        | No                    |
| 3          | Winston    | 9900       | No                    |
| 4          | Luis       | 800        | No                    |
+------------+------------+------------+-----------------------+
Explanation: 
Moustafa paid $400 on "2020-08-01" and received $200 on "2020-08-03", credit (100 -400 +200) = -$100
Jonathan received $500 on "2020-08-02" and paid $200 on "2020-08-08", credit (200 +500 -200) = $500
Winston received $400 on "2020-08-01" and paid $500 on "2020-08-03", credit (10000 +400 -500) = $9990
Luis did not received any transfer, credit = $800

Code

SELECT user_id,user_name,
IFNULL(SUM(CASE WHEN a.user_id=b.paid_by THEN -amount ELSE amount END),0)+a.credit as credit,
CASE WHEN IFNULL(SUM(CASE WHEN a.user_id=b.paid_by THEN -amount ELSE amount END),0)>=-a.credit THEN "No" ELSE "Yes" END as credit_limit_breached
FROM Users as a
LEFT JOIN Transactions as b
ON a.user_id=b.paid_by OR a.user_id=b.paid_to
GROUP BY a.user_id;